solve each of the following in quadratic equations by factoring: x squared + 2x 2x squared = 6x 2a squared + a =0 6m squared + 9m=0 t(2t-3) = 2 what will be the answer
what is the question ?
quadratic equations by factoring ..........
so is it like x(x+2)... ???
yes .. so what are the answer .. ?
1st, x(x+2), 2nd, 2x(x-3), 3rd, a(2a+1), 4th, 3m(2m+3), and final (2t+1)(t-2)
i have more !
can u answer more .. ?
unfortunately :(
why .. ?
@burakb Please show him/her how to do the question, rather than giving just the answers :)
ok .
correct !
@lilyi did you understand how he got the answers?
uhhhmmm .. i dont know ?
.. uhhhmm ... how was it ?
x squared + 2x \[x^2+2x\] now x is common in both terms, so factor out x x(x+ 2)
ok .
how about the step 2 .. ?
there's only one step :) that's the answer
ok..
but the answer are not to be improve .. !
Hmm what? improve?
because thats not a exactly the answer !
then, what is the answer given in your book?
read burakb answer !
"1st, x(x+2) " this is what he posted and that's the same thing i got! :D
yup .. buuuuuuutttttttt ..........
but.. ? Well, if you have more questions please do post it :)
im not right .. , what will be the solution of that !
thats i mean so !
Sorry, i didn't get you! What is your question now?
a(2a+1) .., what are the solution .. ?
its already factored
''solve each of the following in quadratic equations by factoring'' => factor => solve For example, in question one, \[x^2 + 2x=0\]Factor the left side by taking our the common factor x. Then you get: x(x+2) = 0 To solve the equation, put each factor = 0. Since if one of the factor = 0, 0 times other factor can give 0 as the answer, that is the right side. So, x = 0 or x+2 = 0 <- solve these two equations, you'll get x = 0 or x = -2 Got it?
tnx .. yes !
what are the answer .. ?
Can you figure it out?
bbye ..!
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