Question

Find the coordinates of the center and the length of the radius of the following circle.

x 2 + (y - 3) 2 = 8

Answer 1

\((x-h)^2 + (y-k)^2 = r^2\)

Where (h,k) is the center and r is the radius. :-)

Got it?

Answer 2

Hint: (any constant number) \(\pm\) 0 = 0

Answer 3

no

Answer 4

I am confused by that answer.

Answer 5

\(x^2 + (y - 3)^2 = 8\)
can be written as
\((x−0)^2+(y−3)^2=8\)
so it looks like this
\((x-h)^2 + (y-k)^2 = r^2\)
and you can easily figure out the radius and center (re-read what I wrote above)

If r^2 = 8, what does r = ? (hint: What "undoes" a "^2"? Square root yes?)

I'm not sure I can get any more explicit than that... Try it!

Answer 6

thanks