Question

Two ropes, AD and BD, are tied to a peg on the ground at point D. The other ends of the ropes are tied to points A and B on a flagpole as shown below.



Angle ADC measures 60° and angle BDC measures 30°. What is the distance between the points A and B on the flagpole?

40 feet

20 feet

30 feet

10 feet

Answer 1

The whole triangle is a 30-60-90 triangle

Answer 2

your point is?

Answer 3

do you not know how to do 30-60-90 triangles?

Answer 4

nope

Answer 5

Quick question: is this on flvs?

Answer 6

yes

Answer 7

which assessment is this?

Answer 8

04.06 Module Four Review and Practice Test

Answer 9

okay since you have a length on the bottom you know that it is across from the 30 angle. To find the other sides you multiply 10 sqrt3 by 2 for the 90 angle. For the 60 angle, divide 10sqrt3 by sqrt3

Answer 10

what?

Answer 11

\[10\sqrt{3}\times2\]

Answer 12

i got 18.97

Answer 13

did you multiply by 2?

Answer 14

yes

Answer 15

what did you get for 10sqrt3?

Answer 16

9.48

Answer 17

its 17.9 now multiply by 2

Answer 18

17.3 my bad

Answer 19

AD=\[20\]
AC=10

Answer 20

AD=20sqrt3

Answer 21

See first find AC;

\[\tan(60) = \frac{AC}{10 \sqrt{3}} \implies \sqrt{3} = \frac{AC}{10 \sqrt{3}}\]

\[AC = 10 \sqrt{3} \times \sqrt{3} = 30\]

Got it till here?

Answer 22

Now find BC..

\[\tan(30) = \frac{BC}{10 \sqrt{3}} \implies \frac{1}{\sqrt{3}} = \frac{BC}{10 \sqrt{3}} \implies BC = 10\]

Now AB = AC - BC

\[AB = 30 - 10 = 20\]