What are the possible positive, negative, or complex possibilities of 4x^3-9x^2-7x-6
Do you know the rational root theorem?
No I'm new to this. I just want the answer so I can do the others
x=3
then you can solve that and find complex roots.
huh
\( f(3)=0 \)
So 0 for positive?
nope, what's between in the brackets of f(x) is what you insert into the function, therefore 3 is a positive, real root.
Yes but I need the positive, negative, and compleex possible roots
then you will get as a quadratic polynomial \( f(x) = 4x^2+3x+2\) there you only have complex roots.
No negatives?
hmm yes negative complex roots, but no real negative roots
for the complex roots you will get: \( \\ \large x_1 = \frac{1}{8}(-3-i\sqrt{23})\)
and therefore also it's complex conjugate.
compare the given equation with \[a {x ^{2}} + b y^{2}+c\]
How many total zeros
three, it is a polynomial of third degree.
therefore three roots in \(\mathbb{C}\)
So there's 3 complex
nope, the complex numbers include the reals, it's a higher set of numbers. One root \( \in \mathbb{R}\) and two roots \( \in \mathbb{C}\)
Nevermind -____-
where's the problem?
now substitute the values of a,b,c in th equation below\[[-b+\sqrt{(b ^{2}-4a.c)} ]\div2.a\]
well done @mbibin91, by the way, if you don't already know, if you want a nice clean multiplication dot, use \cdot in LaTeX
There's 1 positive 2 or 0 negative and 2 or 0 complex
@Spacelimbus k :)
1 positive, 0 negative (in reals) and 2 complex
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