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How many liters of oxygen gas, at standard temperature and pressure, will react with 25.0 grams of magnesium metal? Show all of the work used to solve this problem. 2 Mg + O2 ----> 2 MgO
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25.0g Mg * (1 mol Mg/24.3050 g Mg) * (1 mol O2/2 mol Mg) * (22.4L O2/1 mol O2)= 11.5L O2
where did 22.4 L of oxygen gas come from?
It's standard. Whenever you convert, 1mole of any volume of gas is always 22.4L
Just like Avogadro's number: 6.02*10^23 particles
ooo.. ok.. thankyou. just wanted to understand. Thank you so much.
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:) Yup! No problem!
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