Question

solve: log(underscore:x)9 = 1/2

Answer 1

_ <--underscore (shift + minus sign)

Answer 2

anyway...
\[\log_x 9 = \frac 12\]

Answer 3

right?

Answer 4

yes igbasallote

Answer 5

that's the equation

Answer 6

\[\log_x 9 = \frac 12\]
first step is to change it into exponential form
\[x^{1/2} = 9\]
do you agree with this form

Answer 7

yes

Answer 8

good. so we need x. you have x^1/2

what do you think you should do to make that x^1/2 into just x^1?

Answer 9

could you log both sides, and bring down the 1/2

Answer 10

hmm not exactly

Answer 11

here's a hint

\[\LARGE (a^3)^{1/3} = a^{3/3} = a^1 = a\]
\[\LARGE (a^2)^{1/2} = a^{2/2} = a^1 = a\]
\[\LARGE (a^{1/3})^3 = a^{3/3} = a^1 = a\]

Answer 12

oh, do you square both sides?

Answer 13

yup

Answer 14

so x = 81?

Answer 15

yup

Answer 16

perfect thanks!