Question

Simplify
(6y^2 -6/ 8y^2 +8y)/(3y -3 / 4y^2 + 4y)

Answer 1

There you can use this:
\[\frac{\frac{A}{B}}{\frac{C}{D}}=\frac{AD}{BC}\]

Answer 2

Where:
A=6y^2 -6
B=8y^2 +8y
C=3y -3
D=4y^2 + 4y
What do we get?

Answer 3

a big number lol

Answer 4

:D Best answer for you!

Answer 5

no!!!

Answer 6

Could you continue? What did you get?

Answer 7

21y+32/28-3y i think

Answer 8

\[ \frac{(6y^2 -6)(4y^2 + 4y)}{(8y^2 +8y)(3y -3)}=\frac{(6y^2-6)}{2(3y-3)}\]

Answer 9

I got that.

Answer 10

so i got it wrong

Answer 11

dont you have to solve that now

Answer 12

Yes, we can do this:
\[\frac{6y^2-6}{2(3y-3)}=\frac{6(y-1)}{6y-6}=\frac{y^2-1}{y-1}\]
And we can do one more step, which one?

Answer 13

take out the 1s

Answer 14

and y^2-y^1

Answer 15

We can use this:
\[y^2-1=(y+1)(y-1)\]

Answer 16

this math is so hard

Answer 17

Pluging that on the numerator., we get this:
\[\frac{(y+1)(y-1)}{y-1}\]
So, the final answer is?

Answer 18

y-1

Answer 19

Sure?

Answer 20

we can cancell out y-1

Answer 21

@brendas The final answer is y+1

Answer 22

i knew that thanks

Answer 23

OK, awsome! i hope I have helped you tonight!

Answer 24

PD: Thanks for the "best response"!! :D