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Proof please. Let a>0 and b>0 if x>a and y>b then 1/xy < 1/ab
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xy>ab
I was gonna say, what is there to prove? seems kinda trivial...
divide by xy...divide by ab
it is
prove that 1/xy < 1/ab
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Proof please. Let a>0 and b>0 if x>a and y>b prove that 1/xy < 1/a
a gave you all you need to do the proof...it is a 2 - 3 line proof (unless you want to be wordy)
can we say that \[x/b>1\] and for these to be true since \[b>0\] ,then also \[x>0\] so we can multiply easily since every thing is + \[(x/a)(y/b)>1\] \[xy/ab>1\] \[xy>ab\] \[1/ab>1/xy\] ... \[1/xy<1/ab\]
just do what Zarkon said: xy>ab divide by xy and what do you get?
didnt see that,thanks
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