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Mathematics 17 Online
OpenStudy (anonymous):

Proof please. Let a>0 and b>0 if x>a and y>b then 1/xy < 1/ab

OpenStudy (zarkon):

xy>ab

OpenStudy (turingtest):

I was gonna say, what is there to prove? seems kinda trivial...

OpenStudy (zarkon):

divide by xy...divide by ab

OpenStudy (zarkon):

it is

OpenStudy (anonymous):

prove that 1/xy < 1/ab

OpenStudy (anonymous):

Proof please. Let a>0 and b>0 if x>a and y>b prove that 1/xy < 1/a

OpenStudy (zarkon):

a gave you all you need to do the proof...it is a 2 - 3 line proof (unless you want to be wordy)

OpenStudy (anonymous):

can we say that \[x/b>1\] and for these to be true since \[b>0\] ,then also \[x>0\] so we can multiply easily since every thing is + \[(x/a)(y/b)>1\] \[xy/ab>1\] \[xy>ab\] \[1/ab>1/xy\] ... \[1/xy<1/ab\]

OpenStudy (turingtest):

just do what Zarkon said: xy>ab divide by xy and what do you get?

OpenStudy (anonymous):

didnt see that,thanks

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