Find a rational zero of the polynomial function and use it to find all the zeros of the function. f(x) = x^4 + 3x^3 - 5x^2 - 9x - 2
are u familiar with rational root theoreom?
yeah I think it is -1,2,-2 but my choices have {1,-2,-2 + sqrt3, -2-sqrt3} this is just an example there is four of them so that confused me
a. {1,-2,-2 + sqrt3, -2-sqrt3} b. {-1,-2,-2 + sqrt5, -2-sqrt5} c. {-1,3,-2 + sqrt5, -2-sqrt5} d. {-1,2,-2 + sqrt3, -2-sqrt3}
-1 , 2 is only rational roots
d is right
or so after that I have to find zero
u must factorise after that to find irrational zeros
okay thanks
i know that x=-1 is a root so i can factor out (x+1) like this \( x^4 + 3x^3 - 5x^2 - 9x - 2=x^4+x^3+2x^3+2x^2-7x^2-7x-2x-2\\=x^3(x+1)+2x^2(x+1)-7x(x+1)-2(x+1)=(x+1)(x^3+2x^2-7x-2) \)
x=2 is a root also so u try to factor out x-2 from degree 3 polynomial , finally u will have a quadratic
so you just place 2 where 1 is right
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