Solve the polynomial inequality and graph the solution set on a number line. Express the solution set in interval notation. x^2 - 4x - 12 <= 0
First, you can split \[x^2 - 4x - 12\] up into two linear terms. Solve the inequality for each of the two terms.
by factoring
Yes, find two numbers that multiply to give 12 and add or subtract to give 4.
okay so I get (x-6)(x+4)
Almost, but not quite. (x-6)(x+2)
oops (x+2)
Now solve the inequality for each of those two terms.
that is where I get lost
my solution sets are a. (6, infinity) b. (-infinity, -2) c. (-infinity, -2)(6, infinity) d. (-2,-6)
my stupid computer keeps freezing up
First set the terms equal to zero and solve for x. You will get two solutions.
so place 0 in x
No, don't place x in for zero. You have this: \[x - 6 = 0\]\[x + 2 = 0\] Solve each of these.
so x= 6 x= -2
That's correct so now you have a numberline that looks thusly: |dw:1342811332171:dw|
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