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OpenStudy (anonymous):
Solve the polynomial inequality and graph the solution set on a number line. Express the solution set in interval notation.
x^2 - 4x - 12 <= 0
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OpenStudy (anonymous):
First, you can split \[x^2 - 4x - 12\] up into two linear terms. Solve the inequality for each of the two terms.
OpenStudy (anonymous):
by factoring
OpenStudy (anonymous):
Yes, find two numbers that multiply to give 12 and add or subtract to give 4.
OpenStudy (anonymous):
okay so I get (x-6)(x+4)
OpenStudy (anonymous):
Almost, but not quite. (x-6)(x+2)
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OpenStudy (anonymous):
oops (x+2)
OpenStudy (anonymous):
Now solve the inequality for each of those two terms.
OpenStudy (anonymous):
that is where I get lost
OpenStudy (anonymous):
my solution sets are
a. (6, infinity)
b. (-infinity, -2)
c. (-infinity, -2)(6, infinity)
d. (-2,-6)
OpenStudy (anonymous):
my stupid computer keeps freezing up
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OpenStudy (anonymous):
First set the terms equal to zero and solve for x. You will get two solutions.
OpenStudy (anonymous):
so place 0 in x
OpenStudy (anonymous):
No, don't place x in for zero. You have this:
\[x - 6 = 0\]\[x + 2 = 0\]
Solve each of these.
OpenStudy (anonymous):
so
x= 6
x= -2
OpenStudy (anonymous):
That's correct so now you have a numberline that looks thusly: |dw:1342811332171:dw|
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