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OpenStudy (turingtest):
\[3^x=9^{x+1}\]?
OpenStudy (anonymous):
Is it??
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
can you show formulas or/and your work please
OpenStudy (anonymous):
You can write it as:
\[3^x = (3^2)^{x+1}\]
\[\large 3^x = 3^{2x+2}\]
Now exponents must be equal..
So equate the exponents and find x from there..
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OpenStudy (anonymous):
so do you cancel the threes and solve for x when you have ^x=2x+2
OpenStudy (anonymous):
See, the two equations are equal..
Their base(3) is also the same..
If they are equal then their exponents must be equal..
So we here equate the exponents..
OpenStudy (anonymous):
In general:
\[\huge x^a = x^b \implies \color{green}{a = b}\]
OpenStudy (anonymous):
I'm still confused I'm not just looking for the answer but I'm better at analyzing the work what values would a and b be
OpenStudy (anonymous):
Here a = x and b = 2x + 2
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OpenStudy (anonymous):
so x=2x+2
OpenStudy (anonymous):
so i subtract from from both sides then subtract x so i get x=-2
OpenStudy (anonymous):
Yes you are right..
OpenStudy (anonymous):
See first his reply..
He replied yes to Turning test..
OpenStudy (anonymous):
oh... so this problem is easier than what i have then....
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