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Find f inverse if f(x) = x^3 + 2 PLease HELP!!
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This can be seen as: \[y = x^3 + 2\] To find the inverse you must swap x for y and solve for y. \[x = y^3 + 2\]
@waterineyes was yours not correct?
It was correct..
His was 100% correct. It's important to see why.
why did you delete it?
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I again provide you the solution: Now I am starting where @qpHalcy0n left: \[x = y^3 + 2\] \[y^3 = x-2\] \[\large \color{green}{y = \sqrt[3]{x - 2}}\]
Now replace y by \(f^{-1}(x)\).
so final answer is f^-1x=cubed root x-2? @waterineyes
Yes it is the answer..
ty
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