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sin^2(t) + tan^2(t)+cos^2(t) equals:
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\(sec^2 \theta\)
You just have to know some trig identities: sin^2(t) + cos^(t) = 1 and then 1 + tan^2(t) = sec^2(t) Enjoy!
Use: \[\sin^2 \theta + \cos^2 \theta = 1\] \[1 + \tan^2 \theta = \sec^2 \theta\]
Can you show me how you got that?
memorise them
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See: Rearrange the terms: \[(\sin^2 \theta + \cos^2 \theta) + \tan^2 \theta\] Use first identity here..
I got it, thank you!
or derive them, cos^2(x)+sin^2(x) = 1 devide all by cos^(x) and see what happens or devide them all by sin^2(x) and see what happens...
Welcome dear..
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