Question

Which of the following triangles is an obtuse triangle?
Answer
A. 6, 10, 12
B. 7, 13, 14
C. 8, 15, 17

Answer 1

you can use Pythagorean Theorem on each triangle, test if each triangle will form a right triangle. If it does, its not an obtuse triangle.

Answer 2

Example, for option A. \[\sqrt{6^{2}+10^{2}}=\sqrt{136}=11.66 or 12\]

Answer 3

Thus, it forms a right triangle, try to do the same process for the other options. :))

Answer 4

@sauravshakya is the answer B

Answer 5

just check i under stand pythangan therom

Answer 6

7, 13, 14

Answer 7

so it is B

Answer 8

The sides are listed in the form \(a,b,c\). The only work you have to do is to check if \(a^2 + b^2 < c^2\).

Answer 9

Not quite.
\[c^2 > a^2 + b^2\]\[14^2 > 13^2 + 7^2\]\[196 > 169 + 49\]\[196 \text{is not greater than } 218\]It's not B.

Answer 10

If the statement holds true, then we have an obtuse triangle.

Answer 11

Bad luck. Check if \(6^2 + 10^2 < 12^2\)

Answer 12

No B is not the answer.

Answer 13

i forgot to add D. 9,9,9√ 2

Answer 14

If \(c^2 = a^2 + b^2\), then it's a right triangle.
If \(c^2 > a^2 + b^2\), then it's an obtuse triangle.
If \(c^2 < a^2 + b^2\), then it's an acute triangle.
It's just a matter of testing the answer choices.

Answer 15

oops. I made a mistake. Yes B is correct answer

Answer 16

@sauravshakya It's not B. :P

Answer 17

@Calcmathlete yeah but if you √ 218 its 14.76 and thats greater than 14

Answer 18

THat's not the theorem though. What matters is if the SQUARED ones are bigger. Not the regular terms.

Answer 19

Yeah B is AN ACUTE TRIANGLE

Answer 20

yeah and its not a right triangle

Answer 21

What are we even doing here?

\( \color{Black}{\Rightarrow 7^2 + 13^2 < 14^2 }\)
\( \color{Black}{\Rightarrow 49 + 169 < 196 }\)
\( \color{Black}{\Rightarrow 218 < 196}\)

Contradiction.

Answer 22

Messi makes me nervous

Answer 23

It's asking for an obtuse triangle. Not an acute triangle @sauravshakya

Answer 24

It's just a repetition of what @Calcmathlete said.

Answer 25

THE CORRECT ANSWER IS A.

Answer 26

that make's it a right triangle

Answer 27

Is the answer D.

Answer 28

It is A like ^ said...
\[c^2 > a^2 + b^2\]\[12^2 > 6^2 + 10^2\]\[144 > 36 + 100\]\[144 > 136\]See? The statement is true.

Answer 29

so the answeer is a

Answer 30

yeah

Answer 31

Yes...do you get why it is A though?

Answer 32

yeah

Answer 33

Alright. Just making sure...