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2x over 3 +6=12 solve?
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\[\frac{2x}{3}+6=12\]?
yup
solve for x?
yeah
subtract 6 from both sides 2x/3+6-6=12-6 2x/3=6 multiply both sides with 3 2x/2*(3)=6*3 2x=18 divide both sides by 2 2x/2=18/2 x=9
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first subtract 6 from both sides \[\frac{2x}{3}+6-6=12-6\] \[\frac{2x}{3}=6\] multiply by 3 to get rid of the fraction \[3(\frac{2x}{3})=6(3)\] \[2x=18\] divide both sides by 2 \[\frac{2x}{2}=\frac{18}{2}\] the 2/2 is 1 \[x=9\]
oh okay thanks guys
yes that the answer.
am getting x = 15 when i begin with 12*3
2x/3+6=12 2x+6=12*3 X=(36-6)/2 X=15
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