Question

Please help me :D

Problem:
Two cars A and B are 200km apart and they are traveling toward each other at the speeds of 28km/h and 22 km/h respectively. When and where will they meet?

2.

If the car A and B in problem 1 start from the same point, going toward the same direction, at what time will they be 18km apart?


3.

If B starts at 1:00pm and gives chase starting at 1:15 from the same point as B, when and where will A overtake B?




Thank you so much for answering!!

Answer 1

1) relative speed =28+22=50
they will meet after 200/50=4 hr
at a distance of 28*4=112 km from the starting poing or (200-112=88 from the other sid)

Answer 2

2) relative speed now =28-22=6
they will be 18 km apart after 18/6 = 3 hr

Answer 3

where did you get 28?

Answer 4

s it 3) in 15min b has already gone 22/4 =11/2 km their relative speed =28-22=6km/hr time required to overtake is (11/2)/6 =11/12 hr =11/12 * 60 =55 mins(after 1:15) i.e at 2:10 and distance from the starting point is 7/6*22 km =77/3 km the speed of A is 28 km/hr as mentioned

Answer 5

what formula did you use?
I really don't know how you did that??????????????

Answer 6

disatnce = speed x time

Answer 7

if two bodies move in same direction their relative speed =difference of their individual speed
if they move in same direction then relative speed is the sum of their individual speeds

Answer 8

ok... proceed

Answer 9

@alynamarie do you agree that distance = speed x time?

it is derived from speed = distance/time

if you cross multiply you get distance = speed x time

Answer 10

yes igbasallote

Answer 11

ok

Answer 12

LGBASALLOTE*

and do you agree that the distance traveled by car A + distance traveled by car B = total distance between them?

Answer 13

yep

Answer 14

uhmm wait..i read the question wrong..

Answer 15

it's alright

Answer 16

Careful....

Answer 17

i thought it was going away...it was towards

Answer 18

so let's start from the beginning heh

Answer 19

Let us start from the start..
He he.

Answer 20

sure :)

Answer 21

uhh feeling repetitive @waterineyes ? lol

Answer 22

Ha ha ha..

Answer 23

Dont want to break the flow of the answers but just a notification for @alynamarie ;

Please post right questions in right group ...

This is a physics question , so please post it in physics section

For further details : http://openstudy.com/code-of-conduct

Answer 24

actually this can be classified as math as well

Answer 25

since it just uses the basic speed = distance/time

Answer 26

Actually @lgbasallote is also right..

Answer 27

-_-

Answer 28

Physics can be fully classified as math.. There is calculation is every where in physics that is basically maths

BUT THEN WHY WE HAVE PHYSICS SECTION RIGHT UP HERE ..

Please obey the code of conduct instead of having arguments against it ..

Thanks!

Answer 29

@lgbasallote isnt *also* right... @lgbasallote *is* right -_- @waterineyes

Answer 30

Don't spam! Common forms of spam include:
Posting a question that is off topic for a particular group (i.e. posting a physics question in the Mathematics group).

-Code of Conduct

Answer 31

@mathslover this is mathematics curriculum NOT physics

Answer 32

Ok so! it is maths ... I didn't know about that @lgbasallote So the physics section and code of conduct are just for enjoyment right ?

Answer 33

alright...you're the ambassador..you know better

Answer 34

dear all i think this is a common topic for maths as well as physics...

Answer 35

@alynamarie by the way did u get the answer ?

Answer 36

@mathslover you can post this question in physics as well as Maths Section..

It is not against the code of conduct..

Answer 37

yup, this is math

Answer 38

I will suppose to continue this discussion with a mod instead .@waterineyes and @all..
BY the way u can continue for the solutions

Answer 39

@mathslover nope, haven't got the answer yet

Answer 40

Should i help u now ?

Answer 41

@mathslover @lgbasallote is helping someone and you just came and you stopped someone to learn..

Couldn't you do this discussion after the question has been solved???

What is the problem in that..

Answer 42

please help me... anyone

Answer 43

even if some body asks other subjects questions
idont think it is wrong
the important thing has to be the question asked has to be answered properly...

Answer 44

The question is of maths and physics both..

Anyone can post it where he wants..

Answer 45

yeah... could someone please help me answer and understand this??
Please :D

Answer 46

Two cars A and B are 200km apart and they are traveling toward each other at the speeds of 28km/h and 22 km/h respectively. When and where will they meet?

Given distance = 200 km.

u = 22 km/h
v = 28 km/h
Let that they will meet at point h..

Hence one part will be : 200 - h and other will be h

Answer 47

I am trying this @alynamarie please wait

Answer 48

ok @mathslover

Answer 49

maybe it's better to solve this in terms of mathematics like their notations. u and v are somewhat physics looking

Answer 50

the process that is shown by @matricked is very right

Answer 51

i know. but i just don't know the formula used

Answer 52

http://en.wikipedia.org/wiki/Relative_velocity

Answer 53

\[\vec{v}_{BA}=-\vec{v}_{AB}\]

Answer 54

ok. that's it 'm closing this yet reposting it in the physics group..... anyone willing to start over :) pleaseee

Answer 55

k thanks .. that is what i was wanting! thanks for ur support

Answer 56

but no one is answering in the physics section

Answer 57

see what i mean..... no one is answering my quetion: posted in the physics section :(

Answer 58

tag people dude
@--- like @mathslover

Answer 59

http://openstudy.com/study#/updates/500a9ae9e4b0549a892efe27

Answer 60

@mathslover I agree with your general sentiment that questions should indeed be posted in the right group so that others in that groups can also benefit from it. However, in this particular instance the question is really in a /grey/ area between maths and physics.
So I believe it was fine for this to be posted here.

Answer 61

k thanks sir

Answer 62

yw :)