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Obtain the general solution using undetermined coefficients method (differential equations): (D^2 - 1) y = 8xe^x
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Find the homogeneous solution first: Using characteristic Equation: \[m^2 - 1 = 0\] m = -1 ,-1
m = 1 and -1 Sorry..
For 1 and -1 solution is given by: \(y_c = Ae^x + Be^{-x}\)
Now make a guess what will you take for particular solution???
particular solution is Ae^x + Bxe^x
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No I think.
no. the homogeneous solution is Ae^x+Be^-x
You can't take because there is already \(e^x\) in the homogeneous solution..
now , obtain the particular solution by substituting , A(x) and B(x) in place of A and B. and then substituting this in the original equation.
ok,
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ok lets solve it
@sami-21 , I advise not to post solutions.
ok @vamgadu
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