Definite integral problem

Question

anonymous · Answer

Not sure what to do with T in the dominator.

anonymous · Answer

try a substitution for the entire denominator.

anonymous · Answer

1/u = lnu

anonymous · Answer

(-;

lgbasallote · Answer

maybe a hint can help

$$\int \frac{dx}{1-x}$$
let u = 1- x
du = -dx

$$\implies -\int \frac{du}{u}$$
$$\implies - \ln u + C$$
$$\implies -\ln (1 -x) + C$$

does that help?

anonymous · Answer

haven't done it myself yet to be honest, just be careful with the substation and therefore with the signs, seems you are missing a minus, see what @lgbasallote posted.

anonymous · Answer

Is that it? it seemed more to it than that hahaha.

Yeah I just noticed the minus sign in missing.

anonymous · Answer

is missing*

anonymous · Answer

simple as that.

lgbasallote · Answer

well actually since your x has a coefficient in this problem it's kind of different

lgbasallote · Answer

u  = 12.77 - 0.12T
du = -0.12dt

see the difference?

anonymous · Answer

yes be careful with the substitution. You will have a reciprocal term of the coefficient leading.

anonymous · Answer

Yeah I see the 12.77 is just a constant.

lgbasallote · Answer

i was actually referring to -0.12.....

anonymous · Answer

Yeah I get you!