Question

If \[\LARGE{\color{red}{(9^n)(3^2)(3^{-n/2})^{-3}-(\sqrt{177147})^n} \over 3^{3m}(2)^3}=\frac{1}{27}\] then:

Answer 1

so let us take \(9^n=3^{2n}\)
hence put \(9^n=3^{2n}\)

Answer 2

a) m-n+2=0
b) 6m+11n-6=0
c)6m-11n-6=0
d)m-n-2=0