Question

simplify (t^2+6t/t-1)-(7/t-1)

Answer 1

both fractions have the same denominator, so you should be able to subtract the numerators directly.

Answer 2

e.g.:\[\frac{a}{b}-\frac{c}{b}=\frac{a-c}{b}\]

Answer 3

so then i should come up with T^2+6t+7/t-1? right ?

Answer 4

not quite - you have added the fractions instead of subtracting them

Answer 5

so then it would -7 instead.

Answer 6

yes - and now you should be able to factorise the numerator in:\[\frac{t^2+6t-7}{t-1}\]

Answer 7

i have to do grouping in order to factor , but what do i do with the denominator ?

Answer 8

just concentrate on the numerator for now - see if you factorise: \(t^2+6t-7\)

Answer 9

i got (t+6)(t+1)?

Answer 10

that doesn't look quite right - that expands to: \(t^2+7t+6\)

Answer 11

you need to find two numbers that multiply to give -7 and add to give +6

Answer 12

well idk what they would be. could it be -1 and + 7.

Answer 13

that is EXACTLY what they would be :)

Answer 14

so now you can use those to factorise the numerator as follows:\[t^2+6t-7=(t-1)(t+7)\]

Answer 15

understand so far?

Answer 16

then i would just wind up with x+7 as an answer because the x-1 would canncel in the numerator and denominator.

Answer 17

perfect!

but remember the variable here is 't' and not 'x'

well done! :)

Answer 18

ohhh duh ! im just used to using x . and thanks for the medal (:

Answer 19

you deserved it. :)

Answer 20

can i bother you with another question?

Answer 21

sure - just post each question in the list on the left please

Answer 22

okayy .