We need to enclose a field with a fence. We have 500 feet of fencing material and a building is on one side of the fencing, so we will not need any fencing along this side. Determine the dimensions of the field that will enclose the largest area.
|dw:1342907652363:dw| let the width be x and length be y then the perimeter is 500 = 2x + y so y = 500 - 2x now the area is A = xy or by substituting A = x( 500 - 2x) A = 500x - 2x^2 next find the 1st and 2nd derivatives \[\frac{dA}{dx} = 500 - 4x\] and \[\frac{dA^2}{d^2x} = -4\] the solution to the 1st derivative will give the maximum area as the 2nd derivative <0 so let 0 = 500 - 4x solve for x to find the stationary points. x = 125 so the maximum area occurs when the width is 125 feet and the length is 250 feet
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