Question

1/2= 14/(6x-2)-6/(3x-1)

Answer 1

http://myalgebra.com/algebra_solver.aspx
Use this link and plug in your problem. its a lifesaver

Answer 2

thanks!

Answer 3

It's important to know why it works. Here you can see that 6x-2 is a multiple of 3x-1

Answer 4

And just to add to that, we could also have re-written the fraction like so

\(\large\frac{1}{2} = \frac{2(7)}{2(3x-1)} - \frac{6}{3x-1}\)

From there we would see that the second fraction can be simplified leaving

\(\large\frac{1}{2} = \frac{7}{3x-1} - \frac{6}{3x-1}\)

And combing the fractions on the right side would yield

\(\large\frac{1}{2} = \frac{7 - 6}{3x-1} \)

Which further simplifies to

\(\large\frac{1}{2} = \frac{1}{3x-1} \)

Which since the numerators are the same, the denominators would also have to be the same in order for the two fractions to be equal thus:

2 = 3x - 1

If we solve for x we get:

2 + 1 = 3x
3 = 3x
3/3 = x
1 = x