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Simplify the expression: (6x^3 − 7x − 4) + (4x^3 + 8x + 3). ^ indicates exponent
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add like terms
First take them out of the parenthesis
\[6x^3-7x-4+4x^3+8x+3\] rearrage them so that all x^3 are next to each other, x^2s and x'sand constants( ones with no x's) \[6x3+4x^3-7x-8x-4+3\] factor out x^3, x and 1 out of each group \[x^3(6+4)+(-7-8)x+1(-4+3)\]
simply add the parenthesis and those will be the coefficients to each group
What would the final answer be?
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I can't give you the final answer if you don't do some work it's against OS conduct
6x^3-7x-4+4x^3+8x-3 6x^3+4x^3-7x+8x-4+3 10^3-x-1
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