Question

11. A car is pulled with a force of 10,000 N. The car's mass is 1267 kg. But, the car covers 394.6 m in 15 seconds

Answer 1

The problem is?

Answer 2

11. A car is pulled with a force of 10,000 N. The car's mass is 1267 kg. But, the car covers 394.6 m in 15 seconds.
(a) What is expected acceleration of the car from the 10,000 N force?
(b) What is the actual acceleration of the car from the observed data of x and t?
(c) What is the difference in accelerations?
(d) What force caused this difference in acceleration?
(e) What is the magnitude and direction of the force that caused the difference in acceleration?

Answer 3

And you can't answer all of them?

Answer 4

letters b c and e

Answer 5

For b, you can use:
x2 = x1 + v1t + (1/2) at^2 assuming x1 and v1 are 0

Answer 6

Friction with the road is causing the car to accelerate slower.
For e, the direction is opposite the motion of the car.
F - F(from friction) = ma
The first F is the force exerted on the car, given in the problem. The second F is from friction, that's what you want to solve the equation for. The a is the acceleration you found in part b, which is slower because of the friction.

Answer 7

tthis one :D A race car exerts 19,454 N while the car travels at a constant speed of 201 mph, 91.36 m/s. What is the mass of the car?

Answer 8

Did you understand the answer to your original question?

Answer 9

whats is the x stands for?

Answer 10

x is the distance. So x1 = 0 because that's your starting point.
x2 = 394.6 m because that's the final distance