Simplify
\[\frac{\sqrt{6}}{\sqrt{2}} + \frac{3}{\sqrt{3}} + \frac{\sqrt{15}}{\sqrt{5}} +\frac{\sqrt{18}}{\sqrt{6}}\]
Remember one thing: \[\large \color{green}{\frac{\sqrt{x}}{\sqrt{y}} = \sqrt{\frac{x}{y}}}\]
So for first term apply this formula... and tell me what do you get..??
@mathslover will suggest you to take the rationalization process I guess..
\[\large{\frac{\sqrt{6}}{\sqrt{2}}=\sqrt{\frac{6}{2}}}\] \[\large{\sqrt{6}=\sqrt{3}}\] \[\large{\frac{3}{\sqrt{3}}}\]Now rationalizing the above expression
Every term will contain 3 after solving Strange WOW..
yes i get it, but then how do i simplify later
sorry i meant : \(\frac{\sqrt{6}}{\sqrt{2}}=\sqrt{3}\)
yes there are three terms like that and the other one 3/root 3
What do you get show us first..
|dw:1342950785620:dw|
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