Question

Find the area of the region bounded by the graphs of y = x^2; x = 0; x = 2; and the x axis.

Answer 1

integrate ion of x^2 =(x^3)/3
thus the answer is 8/3 -0/3 =8/3

Answer 2

the area you need is
\[\begin{align}
\int_{0}^{2}x^{2}dx &=\frac{x^{3}}{3} \text{ from 0 to 2. }\\
&=\frac{2^{3}}{3}-\frac{0^{3}}{3}\\
&=\: \frac{8}{3}\\
\end{align}\]