how to find the first three derivatives of f(x)=2x^5 + x^(3/2) - (1/2x)?

Question

klimenkov · Answer

You want to understand how or just to know the answer?

anonymous · Answer

Its just basic derivative....

anonymous · Answer

isn't it the 1st derivative for (-1/2x ) is (1)/(2x^2)? can you explain to me how did (-1/x^3) became the 2nd derivative for (-1/2x)?

anonymous · Answer

@klimenkov

anonymous · Answer

@Mitul

anonymous · Answer

For derivative, the rule is u go on decreasing the power of the variable and multiply that variable with that power each time u take derivative...

klimenkov · Answer

You are right. The first derivative for $-\frac1{2x}$ is $\frac{1}{2x^2}$. The second derivative is $\left (\frac{1}{2x^2} \right) '$. Can you find it?

anonymous · Answer

see (-1/(2x)) means (-1/2)*x^(-1)
first derivative : (-1/2)*-1*x^(-2)
Second derivative : (-1/2)*-1*-2*(x^-3) and so on

anonymous · Answer

thanks..:)

anonymous · Answer

@Mitul how to find its third derivative?