Mathematics
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OpenStudy (kaiz122):
integrate this one please......
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OpenStudy (kaiz122):
\[\int\limits_{}^{} \frac{\sqrt{x}+5}{\sqrt{x}-2} dx\]
OpenStudy (anonymous):
I think you should prefer Rationalization here..
OpenStudy (kaiz122):
yes, please, i have my answer but i checked it by differentiation, and i got a wrong answer, i want know where is my mistake
OpenStudy (anonymous):
You should show your work so that we can find where you have done wrong..
OpenStudy (kaiz122):
ok,
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OpenStudy (anonymous):
Need not to be fast..
Take your time..
OpenStudy (kaiz122):
oh, it's alright now, i saw where i've done wrong. thanks though. :)
OpenStudy (anonymous):
Sure??
OpenStudy (kaiz122):
help me again please. @waterineyes
OpenStudy (anonymous):
Where??
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OpenStudy (kaiz122):
can you show me how you solve it? i'm confused
OpenStudy (anonymous):
I said you to use rationalization here..
Multiply and divide by \(\sqrt{x} + 2\)..
OpenStudy (anonymous):
just take \[\sqrt{x}=t\]
OpenStudy (anonymous):
write, \[\sqrt{x}+5=\sqrt{x}-2 +3\]
OpenStudy (anonymous):
that means x=t^2 and dx=2tdt
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OpenStudy (anonymous):
then the integration becomes,
\[(1+3/t-2 )2tdt\]
OpenStudy (anonymous):
i think you can go ahead from here?
OpenStudy (kaiz122):
ok, thanks. :)
OpenStudy (anonymous):
rationalize it will get easy .
OpenStudy (anonymous):
@sami-21 i think rationalising makes it a lil difficult.never mind. thats my opinion
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OpenStudy (kaiz122):
after having \[2\int\limits_{}^{} \frac{u^2 +5u}{u-2} du\]
what shal i do?
i tried using long division, and after that,
OpenStudy (kaiz122):
@vamgadu @waterineyes
OpenStudy (anonymous):
stick with the long division, that's the way to go.
OpenStudy (anonymous):
How did you get it??
OpenStudy (anonymous):
you should get something like that.
\[ u+7+\frac{14}{u-2}\]
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OpenStudy (kaiz122):
i got \[2\int\limits_{}^{} (u+7+\frac{14}{u-2}) du\]
OpenStudy (anonymous):
Separate them..
OpenStudy (kaiz122):
then i got \[u^2 +14u+28 \ln |u-2|+ C\]
OpenStudy (anonymous):
Absolutely...
OpenStudy (anonymous):
What else you want??
This is the answer dude..
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OpenStudy (anonymous):
not quiet, back substitution
OpenStudy (kaiz122):
if i substitute \[\sqrt{x} =u\]
OpenStudy (anonymous):
Of if you made any substitution then replace u by that..
OpenStudy (kaiz122):
i got \[x +14\sqrt{x} +28 \ln |\sqrt{x} -2| +C\]
OpenStudy (anonymous):
Right..
Well done..
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OpenStudy (kaiz122):
but if i get the dervative of it, i should have obtained the problem, but i don't.
OpenStudy (kaiz122):
oh, i got it already. when i get the derivative of x i thought it was 0, it should be 1, thanks to you all!! :)