Question

how to solve for the first derivative of f(x)=sin(x)cos(x)?

Answer 1

that's the product rule you will want to use there. Familiar with it?

Answer 2

no...

Answer 3

\[ f(x)=u(x)\cdot v(x) \\ f'(x)=u'(x)\cdot v(x) + u(x) \cdot v'(x) \]

Answer 4

\[\large \color{green}{ uv = u.v' + v.u'}\]

Answer 5

what is the derivative for sin x?

Answer 6

better this way
1/2 sin 2x

Answer 7

\[\frac{d}{dx}(sinx.cosx) = sinx \times \frac{d}{dx}(cosx) + cosx \times \frac{d}{dx}(sinx)\]

Answer 8

Go with experimentx @unkabogable

Answer 9

both are equivalent.

Answer 10

how did f'(x)=cos^2(x)-sin^2(x) is the answer?

Answer 11

@waterineyes

LaTeX tip -- use \cdot instead of "." :-p

\[\huge f\cdot g \text{ vs } f .g\]

Answer 12

Okay Sir...