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Mathematics 14 Online
OpenStudy (anonymous):

What is the standard form of the equation of the circle in this graph?

OpenStudy (anonymous):

Parth (parthkohli):

You must determine the \(\textbf{center}\) first. Can you tell me what it is?

OpenStudy (anonymous):

Sure! I just posted the image I'm given.

Parth (parthkohli):

Hmm. So can you tell me what the center is from that graph?

OpenStudy (anonymous):

The center is (-3, 1)

Parth (parthkohli):

Good job—now can you tell me the equation of a circle?

OpenStudy (amistre64):

might wanna find radius first ... since your gathering the parts

Parth (parthkohli):

Yep, I agree. I don't think that there is a circle given, so we'd just keep it \(r^2\).

OpenStudy (anonymous):

Maybe the blue part is the circle?

OpenStudy (amistre64):

teh blue outline is the circle, the red dot is the center

Parth (parthkohli):

Oh, yes. I thought that they made it as an outline for the beauty ;)

OpenStudy (anonymous):

I wish I could give you more information/help, but I am clueless on these types of questions. Here are the answers I am given.

Parth (parthkohli):

Do you know the radius of the circle?

OpenStudy (amistre64):

the answers at least tell us what form they want, since i can never recall what the different names go to :)

OpenStudy (anonymous):

The radius is 1, diameter is 2

Parth (parthkohli):

Yes, it is. I know that you know that I know that you know that you know what the equation of a circle is ;)

Parth (parthkohli):

Since the last question you asked gave you the equation of a circle, I suppose that you still know it.

OpenStudy (anonymous):

ohhhhhhh, is it (x-3)^2+(y+1)^2=2? I am so durp.

OpenStudy (amistre64):

if we know the center (cx,cy) and the radius r; we just fill those into the formula: \[(x-cx)^2+(y-cy)^2=r^2\]

OpenStudy (amistre64):

r^2 not= 2 for starters

Parth (parthkohli):

Yep.

Parth (parthkohli):

\(r^2 = (1)^2\)

OpenStudy (anonymous):

I got it amistre64, thank you both, you're awesome.

Parth (parthkohli):

You're welcome!

OpenStudy (amistre64):

youre welcome, but the answer youve posted is in error

Parth (parthkohli):

Amistre played a big role here, so I want to thank him too :)

OpenStudy (anonymous):

@amistre64 I have never seen the c there before. What's the purpose? I've only see it in the form: \[(x - h)^2 + (y - k)^2 = r^2\]

Parth (parthkohli):

What's \(1^2\)? @heavenseven77

Parth (parthkohli):

@Calcmathlete different notations. c means 'center'.

OpenStudy (amistre64):

cx stands for center x component cy stands for center y component seems more intuitive to me than h adn k

OpenStudy (anonymous):

oh ok alright thanks.

OpenStudy (amistre64):

the original poster seems to ha ve moved on, prolly taking a timed "thing" and doesnt have time for the details :)

OpenStudy (anonymous):

I think I got it. Thought I closed this thing??

Parth (parthkohli):

But we still are allowed to post here. ;)

OpenStudy (amistre64):

closed doesnt mean gone; just takes it off the board to make room for others

OpenStudy (amistre64):

our concern is that the answer you suggested doesnt fit the correct answer that we know it to be

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