Question

Use ∆ABC to answer the question that follows.

Given: ∆ABC

Prove: The three medians of ∆ABC intersect at a common point.

When written in the correct order, the two-column proof below describes the statements and justifications for proving the three medians of a triangle all intersect in one point.

Answer 1

Statements
Justifications
Point F is a midpoint of
Point E is a midpoint of
Draw
Draw
by Construction
Point G is the point of intersection between and
Intersecting Lines Postulate
Draw
by Construction
Point D is the point of intersection between and
Intersecting Lines Postulate
Point H lies on such that ≅
by Construction
I
BGCH is a parallelogram
Properties of a Parallelogram (opposite sides are parallel)
II
≅
Properties of a Parallelogram (diagonals bisect each other)
III
and
Substitution
IV
and
Midsegment Theorem
is a median
Definition of a Median

Answer 2

2, 3, 4, 1

Answer 3

I dont have that as an option..
Which is the most logical order of statements and justifications I, II, III, and IV to complete the proof?

III, IV, II, I

IV, III, I, II

III, IV, I, II

IV, III, II, I

Answer 4

@J.L.

Answer 5

Midsegment Theorem, Substitution, Properties of a parallelogram (opp sides are parallel), properties of a parallelogram (diagonals)

Answer 6

4,3,2,1..?

Answer 7

You're two-column justification isn't proper...I'm going by on what I put on my quiz

Answer 8

I actually pulled yours up and compared it to mine.

Answer 9

What?

Answer 10

The question you asked a while ago. I pulled up the document that you posted and compared it to mine

Answer 11

I got the question right

Answer 12

Ya, and when I compared it to mine, I got it right also :)

Answer 13

Medal?