Question

what is the integral of (1/x^2)

Answer 1

-1/x

Answer 2

(1/x^2) is the same as X^-2

so you add on to the power, become X^-1 and then divide by that power.

so it becomes x^-1/-1

which simplifies with positive indices to -1/x but don't forget to +c :)

So your answer is -1/x +c

Answer 3

x^-2 would be -1/x

Answer 4

+c

Answer 5

thank you very much