Question

A movie stunt driver on a motorcycle speeds horizontally off a 50.0-m-high cliff. How fast must the motorcycle leave the cliff top to land on level ground below, 90.0 m from the base of the cliff where the cameras are? Ignore air resistance.
can anyone help me?

Answer 1

First, find the time it takes for him to hit the ground. Because there is no initial velocity in the y direction, it is free fall downward. Use:
x2 = x1 + v1t + (1/2)at^2 with x2 = 0 and v1 = 0
to find the time.

Use the same equation to find the initial velocity in the x direction, using the time you just calculated. In the x direction, the velocity is constant, there's no acceleration, so a = 0.

Answer 2

thanks for ur answer