please help, \[14C _{5} + 7!- 17!/3!14!\] the answer is 6362 but i keep getting a different answer on my calculator
the 14 should be small like the 5
ok - lets look at this one term at a time. what do you get for \(_{14}C_5\)?
i get 2002
that is correct. and 7! ?
i have a ti-84 and i use the nCr
5040
also correct. so you must have made a mistake in the last term - what did you get for that?
5.16803703E24
that is definitely wrong
\[\frac{17!}{3!14!}=\frac{17*16*15*\cancel{14!}}{3!*\cancel{14!}}=\frac{17*16*15}{3*2}\]
ohh ok i was just putting it straight in my calculator so ill try it like that and let you know if i get it right
it looks like what you actually calculated was:\[\frac{17!}{3!}\times14!\]
does your calc have brackets? i.e. can you enter '(' and ')'?
if it does, then you can try:\[17!\div(3!\times4!)\]
the 4! should be 14! up there
yes my calculator does. i calculated the whole equation separately but still did not get the answer
2002 + 5040 - 680 = 6362
i didn't get the 680 i got 2720
use the brackets as I suggested and recalculate it please
just got it! lol I guess it didn't work before because i did it as 14nCr +7! (17!/3!4!) thank you i got it now!
you need to be careful with equations like:\[\frac{ab}{cde}\]when using a calculator. always enter this as:\[a\times b\div (c\times d\times e)\]
would i be able to do (ab/(cde))?
yes - that would also work.
thank you for your help :)
yw :)
would you happen to know about sequences?
I do but unfortunately it is very late here and I need to get some sleep now. Just post it as a new question and I'm sure there will be plenty of other people here willing to help you out.
ohh ok thank you! good night!
thx - good night!
Join our real-time social learning platform and learn together with your friends!