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OpenStudy (anonymous):

find the number of molecules and atoms of hydrogen in CH4

OpenStudy (anonymous):

is it 6.022 * 10 ^23 molecules...

OpenStudy (anonymous):

@Callisto

OpenStudy (callisto):

It should be...

OpenStudy (anonymous):

then wat abt no of atom

OpenStudy (anonymous):

is it 6.022 * 10^23

OpenStudy (callisto):

One mole of CO2 => one mole of C So, it should be..

OpenStudy (anonymous):

if the question is to find the number of molecules of hydrogen in CH4 then..

OpenStudy (callisto):

One mole of CH4 => 4 moles of H => no. of mole of CH4 x Avogadro's constant x 4

OpenStudy (anonymous):

1 mole CH4 means 4 atoms of hydrogen...

OpenStudy (anonymous):

hw it is 4 moles

OpenStudy (callisto):

1 CH4 molecule => 4 H atoms 1 mole of CH4 molecules => 4 mole of H atoms

OpenStudy (callisto):

*4 moles

OpenStudy (anonymous):

ok then it is 4*6.022* 10 ^23 molecules!!

OpenStudy (callisto):

H atoms!!! not really molecules!!

OpenStudy (anonymous):

then 6.022*10^23 molecules of h2

OpenStudy (callisto):

May I know what your exact question is?

OpenStudy (anonymous):

find the number of molecules and atoms of hydrogen in CH4

OpenStudy (chmvijay):

Avogadro number of molecules

OpenStudy (callisto):

Number of molecules = Avogadro constant x number of mole of CH4 Number of atoms of H = Avogadro constant x number of mole of CH4 x 4 If I remember correctly

OpenStudy (anonymous):

yup thxx

OpenStudy (anonymous):

Mole is a number just like dozen. The number for dozen is 12 and the number for mole is 6.022 X 10^23. Now this would be for molecules in a mole of a molecular compound. If you were talking about atoms in a mole of an atomic element like gold, the answer would be 6.022 X 10^23 atoms. The only trick you run into is if you were asked how many atoms there are in a mole of CO2. In this case, there are still 6.022 X 10^23 molecules of CO2, but there are three atoms to each molecule of CO2 (One carbon and two oxygen atoms), therefore there would be 3(6.022 X 10^23) atoms in one mole of CO2.

OpenStudy (anonymous):

@Yahoo! it think this will hlp u out.

OpenStudy (anonymous):

@Ruchi. plzz read my question now i have made some corrections to it..

OpenStudy (callisto):

@Ruchi. Please don't copy and paste answer from other site!

OpenStudy (anonymous):

@Callisto ohh really she want my hlp and i hav hlp her out it nt meanning ful to past it some where else or nt .it matter that i hav hlp her or nt or if i hav pasted it from some where else then why don't u tell the source to @Yahoo!

OpenStudy (callisto):

Sorry, I type all the above myself, I didn't copy it from somewhere else. If I really need to tell a source, that is my teacher. But in your case, you're probably copying from Yahoo! Answers: http://answers.yahoo.com/question/index?qid=20091124190426AA7qTEs In that case, you'd better cite your reference.

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