Question

Assign the position of the element having outer electronic configuration

(i) ns2 np4 for n = 3 (ii) (n - 1)d2 ns2 for n = 4, and (iii) (n - 2) f7 (n - 1)d1 ns2 for n = 6, in the periodic table?

Answer 1

@apoorvk @Callisto

Answer 2

@UnkleRhaukus

Answer 3

(i) \(ns^2 np^4\) \(n=3\)
\[\qquad 3s^23p^4\]

Answer 4

so it belongs to 3 rd period and group 16

Answer 5

right,

Answer 6

then (ii) (n - 1)d2 ns2 for n = 4

Answer 7

it confuses

Answer 8

it belongs to 4 th period but wat abt the group

Answer 9

\[(n-1)d^2\quad ns^2\qquad\qquad n=4\]
\[3d^2\quad 4s^2\]

Answer 10

ao group 4 or 14

Answer 11

@UnkleRhaukus

Answer 12

?

Answer 13

does this belongs to group 4

Answer 14

or 14

Answer 15

@UnkleRhaukus r u there!!

Answer 16

how could it be 14?

Answer 17

yup u r correct it is 4

Answer 18

group 14 would be p block

Answer 19

s

Answer 20

then the last one

Answer 21

6 th period and 3 rd group is it correct????? @UnkleRhaukus

Answer 22

(iii) \( (n - 2) f^7 (n - 1)d^1 ns^2\) for \(n = 6\)

\[4 f^7 5d^1 6s^2\]
\[\text{Gd}\]