Question and my solution in link:

https://img.skitch.com/20120724-nncamkwixfh2r3agndarby9hjh.jpg

Question

Question and my solution in link:

https://img.skitch.com/20120724-nncamkwixfh2r3agndarby9hjh.jpg

vincent-lyon.fr · Answer

You have forgotten the weight of the ball.

vincent-lyon.fr · Answer

Resolving N's 2nd law on vertical and horizontal, you should find:

$T_1-T_2=\Large\frac{Mg}{\sin\alpha}$

$T_1+T_2=\Large\frac{Mv^2}{l\:\cos^2\alpha}$

where $l$ is the length of each string.

australopithecus · Answer

how did you get these formulas ugh

vincent-lyon.fr · Answer

Resolving N's 2nd law on vertical and horizontal !

australopithecus · Answer

ok then

anonymous · Answer

i got the same values for r and theta. but as vincent sir already pointed out, u forgot the weight of the object.
but my eqs, differ a little. i got:
$$T _{1} + T _{2} = mv ^{2}/rcos \alpha $$
$$T _{1} - T _{2} = mg/\sin \alpha $$

anonymous · Answer

this is what i did:
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