Question

Question and my solution in link:

https://img.skitch.com/20120724-nncamkwixfh2r3agndarby9hjh.jpg

Answer 1

You have forgotten the weight of the ball.

Answer 2

Resolving N's 2nd law on vertical and horizontal, you should find:

\(T_1-T_2=\Large\frac{Mg}{\sin\alpha}\)

\(T_1+T_2=\Large\frac{Mv^2}{l\:\cos^2\alpha}\)

where \(l\) is the length of each string.

Answer 3

how did you get these formulas ugh

Answer 4

Resolving N's 2nd law on vertical and horizontal !

Answer 5

ok then

Answer 6

i got the same values for r and theta. but as vincent sir already pointed out, u forgot the weight of the object.
but my eqs, differ a little. i got:
\[T _{1} + T _{2} = mv ^{2}/rcos \alpha \]
\[T _{1} - T _{2} = mg/\sin \alpha \]

Answer 7

this is what i did: