two blocks A and B each of mass m are placed on a smooth horizontal surface . two horizontal forces F and 2F are applied on both the blocks A and B respectively. Block A does not slide over block B. Then the normal reaction force acting between the blocks is?
a)F
B)F/2
C)F/(sqrt of 3)
d) 3 F
answer is 3F. Can anyone guide me how to get there?

Question

two blocks A and B each of mass m are placed on a smooth horizontal surface . two horizontal forces F and 2F are applied on both the blocks A and B respectively. Block A does not slide over block B. Then the normal reaction force acting between the blocks is? 
a)F
B)F/2
C)F/(sqrt of 3)
d) 3 F
answer is 3F. Can anyone guide me how to get there?

anonymous · Answer

can u draw a picture it would be easier

anonymous · Answer

The normal reaction force acting between blocks can be found by adding forces
F + 2F = 3F
if you have A and B on a horizontal surface you have:
|dw:1343239986345:dw|
normal reaction is the total force in that point