Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
i started factoring and got 5(x+1)/(x+5)(x+3)=0 but im not sure what to do after....so i just take the denominator and try to figure it out from there?
OpenStudy (anonymous):
Do you have to find restrictions and/or solve for x?
OpenStudy (anonymous):
solve for x
OpenStudy (anonymous):
Alright. You would have the right approach if you were simplifying. However, here, just solve for x regularly.
\[\frac{5x + 5}{x^2 + 8x + 15} = 0 \implies 5x + 5 = 0 \times (x^2 + 8x = 15) \implies 5x + 5 = 0\]Can you solve from there?
OpenStudy (anonymous):
im not sure if i understand what you did
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Alright. You have x in both the denominator and numerator. Therefore, you multiply both sides by what's in the denominator so that you can solve for x.
OpenStudy (anonymous):
Since 0 times anything is 0, that cancels out.
OpenStudy (anonymous):
right
OpenStudy (anonymous):
so now you just solve for x here:
5x + 5 = 0
OpenStudy (anonymous):
super easy! i get it
Still Need Help?
Join the QuestionCove community and study together with friends!