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Mathematics 21 Online
OpenStudy (anonymous):

Use differentiation to find a power series representation for: a.) 1/(1+x)^2 b.) use part a. to find a power series for: 1/(1+x)^3. I can do the first part, but I cant figure out the second part. I am using the stewart calc book so I cant figure it out by the examples, and the solutions manual skips steps. Please help!!!

OpenStudy (anonymous):

Pix of both problem and solution.

OpenStudy (anonymous):

is it cool to pm him?

OpenStudy (eyust707):

Of course! Zarkon you have any ideas??

OpenStudy (zarkon):

yes

OpenStudy (anonymous):

not sure how the -1/2 got in front of the d/dx

OpenStudy (eyust707):

So from part a you get that: \[f(x)= \sum_{0}^{\infty} (-1)^n (n+1)x^n \]

OpenStudy (eyust707):

Then you take the derivative of the series.

OpenStudy (eyust707):

and the derivative of the function..

OpenStudy (eyust707):

These two are still equal and on the right hand side you have a function with 1/(1+x)^3 in it

OpenStudy (eyust707):

left*

OpenStudy (anonymous):

ok, take d/dx of series u posted, equal it to 1/(1+x)^3?

OpenStudy (eyust707):

no you can rearrage the equation so just that is on the left hand side

OpenStudy (eyust707):

here check this out:

OpenStudy (eyust707):

All they did was differentiate both sides, then divide both sides by -2

OpenStudy (eyust707):

Then change your indexes so that it is a valid power series and we have x^n

OpenStudy (anonymous):

thats where I am lost where did the -2 come from?

OpenStudy (anonymous):

nvmn

OpenStudy (eyust707):

=P

OpenStudy (anonymous):

i see it now.

OpenStudy (anonymous):

damn ok thanks for the help. got final tomorrow and been at this all day. think its time for a break.

OpenStudy (eyust707):

damn good luck!

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