log3(x+2)+log3(x+1)=2 exact solution...
you know the properties of logs? you can write the expression on the left side as 1 logarithm... can you do that?
I have it as log(3x+6)+log(3(x+1))-2
use this property: \(\large log_bM + log_bN=log_b(M\cdot N) \)
wait.. what is this the problem: \(\large log3(x+2)+log3(x+1)=2 \) or \(\large log_3(x+2)+log_3(x+1)=2 \)
log3(x+2)+log3(x+1)=2
so this is log base 10 ???
yes
ok... the property still applies no matter what base we're talking.... can you write out the expression on the left as ONE logarithm (with base 10)???
I don't know how to do this problem, the answer I am getting is x=-3/2+1/6 =sqrt 409 I need exact solution and move decimel 3
how are you getting that answer (if you don't know how to do this problem?)
I have it set up as log(3x+6)+log(3(x+1))-2 am I not setting it up write? My answer don't seem right
since you said this is log base 10, then \[\large log3(x+2)+log3(x+1)=log[3\cdot 3\cdot (x+2)\cdot (x+1)] \] \[\large =log[9\cdot (x^2+3x+2)] \] \[\large =log(9x^2+27x+18) \] so now your equation looks like this: \(\large log(9x^2+27x+18)=2 \)
Ok, my answer is 100?
Join our real-time social learning platform and learn together with your friends!