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9x^2=25 x=??????
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x^2/9 = 25/9 take the square roots x = 5/3
x^2 = 25/9 x = sqrt(25/9) x = sqrt(25)/sqrt(9) x = 5/3
\[\LARGE{9x^2=25}\]\[\LARGE{x^2=\frac{25}{9}}\]\[\LARGE{x=\sqrt{\frac{25}{9}}=\frac{5}{3}}\]
will -5/3 also work?
\[9x^2 = 25\] \[\sqrt{9x^2} = \sqrt{25}\] \[\pm 3x = \pm 5\] \[x = \pm \frac 53\] does that answer your question?
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\[\Huge{x=\frac{\pm5}{\pm3}}\]
thnx
ur welcome:)
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