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Mathematics 39 Online
OpenStudy (anonymous):

9x^2=25 x=??????

OpenStudy (anonymous):

x^2/9 = 25/9 take the square roots x = 5/3

OpenStudy (anonymous):

x^2 = 25/9 x = sqrt(25/9) x = sqrt(25)/sqrt(9) x = 5/3

OpenStudy (theviper):

\[\LARGE{9x^2=25}\]\[\LARGE{x^2=\frac{25}{9}}\]\[\LARGE{x=\sqrt{\frac{25}{9}}=\frac{5}{3}}\]

OpenStudy (anonymous):

will -5/3 also work?

OpenStudy (lgbasallote):

\[9x^2 = 25\] \[\sqrt{9x^2} = \sqrt{25}\] \[\pm 3x = \pm 5\] \[x = \pm \frac 53\] does that answer your question?

OpenStudy (theviper):

\[\Huge{x=\frac{\pm5}{\pm3}}\]

OpenStudy (anonymous):

thnx

OpenStudy (theviper):

ur welcome:)

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