Question

Find the general solution of tan2x = -cot(x+pie/3)?

Answer 1

u kno tan2x = 2tanx/1-tan^2x nd cotx = 1/tanx

Answer 2

form a quadratic nd solve........ for tanx........ then u l get the g.s

Answer 3

\[\tan(2x) = -\cot(90 + x -30) \implies -(-\tan(x-30)) = \tan(x - \frac{\pi}{6})\]

\[\implies \tan(2x) = \tan(x - \frac{\pi}{3})\]

Answer 4

General solution is given by:

\[\tan ( \theta) = \tan(x)\]

then:

\[\theta = n \pi + x\]

Answer 5

so:

\[2x = n \pi + ( x - \frac{\pi}{3} ) \implies x = n \pi + \frac{\pi}{3}\]

Answer 6

hey @waterineyes but my books says it as x = n pie + 5pie/6

Answer 7

So put n = 0 1 2 3 4 etc etc and find the corresponding value of x..

Answer 8

you can subtract it from \(2 \pi\)..

Answer 9

wat???

Answer 10

Wait something got wrong..

Let me check..

Answer 11

@w\ r uthere

Answer 12

Wait I am checking it..

Answer 13

I got it..