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Physics 29 Online
OpenStudy (anonymous):

A positive point charge /( q /) is placed at the center of an uncharged metal sphere insulated from the ground (See attachment). The outside of the sphere is then grounded as shown. /( A /) is the inner surface and /( B /) is the outer surface of the sphere. What is the charge on A and B each? Attachment: https://dl.dropbox.com/u/63664351/Charge.PNG

OpenStudy (anonymous):

u kno wen grounded potential of that surface = 0

OpenStudy (anonymous):

+ve charge at center will create negative charges all over b but it is grounded so the negative charge will be neutralized so at inner serface charge will be still +ve and at B serface will be neutral bbu tyou dont believe fools so wai tfor another reply. . .

OpenStudy (anonymous):

@theyatin i think the +q at the center will polarize the metal sphere such that there'll be -ve charges concentrated all over A (inner surface) and equal +ve charges concentrated over B(outer surface). now this part i'm not entirely sure of, so please feel free to correct me. now, B is grounded. so the +ve charge on B will attract equal amt on -ve charge from the 'ground' and thus the surface B becomes neutral. so the end answer is, A has -ve charge, while B is neutral.

OpenStudy (anonymous):

i guess, that happens. but i'm sure, that at one point A will be -ve and B will be neutral. then because of the repulsive force between the -ve charges, they'll move to B. then because of grounding B again becomes neutral. so, we're back at square one. and then again induction takes place. i think this process will stop when the attractive force between the +q at the center and the -ve charges on A will be stronger than the repulsive force between the -ve charges. so in the end again, A will be -ve and B will be neutral. not too sure though. this is what i think.

OpenStudy (anonymous):

Thanks @Vaidehi09. Yeah your answer make sense and one of the multiple-choice contain your answer. On the other hand your answer @theyatin is not on the choice. Here are the choices: a) The charge on A is –q; that on B is +q. b) The charge on B is –q; that on A is +q. c) There is no charge on either A or B. d) The charge on A is –q; there is no charge on B Che. You are wrong. Again.

OpenStudy (anonymous):

great! this confirms that my logic is correct! thanks :)

OpenStudy (anonymous):

yup, @Vaidehi09 's logic is correct

OpenStudy (anonymous):

@Vaidehi09 oh yup vaidehi you are right sorry for wrong interpretation. . .

OpenStudy (anonymous):

@student92 for a fool they say once wrong is always wrong. . .

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