Question

Solve for x
e^(2x)+2e^(x)-8=0

Answer 1

let u = e^x

Answer 2

\[u^2 + 2u - 8=0\]

Answer 3

i think that you're able to do it now

Answer 4

Clever girl

Answer 5

and dont forget to sub back in the \(u\) to solve for \(x\)

Answer 6

\[
2 e^x+e^{2
x}-8=\left(e^x-2\right)
\left(e^x+4\right)=0
\]

Answer 7

As @Mimi_x3 said, it should be easy from now on.

Answer 8

yeah; your method is easier.

Answer 9

I got it, thanks:)
How about:
log(x-3)=2?

Answer 10

i think that you should post it in another question..