Question

f(x)=x^2+1; g(x)=sqrtx-9
Find domain

Answer 1

Domain of f(x): All real numbers.
Domain of g(x): All real numbers >=9.

Answer 2

Was -9 under the square root symbol too?

Answer 3

Thank you!!

Answer 4

The domain of \(f\) is \(\mathbb R\). The domain of \(g\) is \(\{x\in\mathbb R:x\ge9\}\). This is assuming that \(g(x)=\sqrt{(x-9)}\) as opposed to \(g(x)=\sqrt x - 9\).

Answer 5

If it's under the square root symbol then @myko is correct.

If not, then my response is correct.

Answer 6

Actually, your response is not correct in either case. Being a whole number has nothing to do with it. If it's not under the square root the answer is the positive reals.

Answer 7

I advise you to use parentheses when possible.

Answer 8

@nbouscal good point. I was thinking positive reals and wrote whole number

Answer 9

Domain of f(x): All real numbers.
Domain of g(x): All real numbers >=9. (If sqrt(x-9))

Domain of f(x): All real numbers.
Domain of g(x): 0 and all positive real numbers (If sqrt(x) -9)