Question

help- Is this true? The limit of sinx/x=1as x approaches infinity.

Answer 1

uhhhhhhhhhh..... I don't think so

Answer 2

This is false. The limit is actually zero because as x goes through the function in the numerator, the result will always be small, and the denominator will always be larger and exponentially larger as it increases.

Answer 3

Ok that's what I thought, but wasn't sure. What about this? \[\lim_{x \rightarrow 0} \left| \sin x \right|/x =1\]

Answer 4

Yes that's right

Answer 5

Wait no, I didn't notice the absolute value brackets. You would get two different limits from both sides of 0, thus the limit does not exist...

Answer 6

for someone confused about calculus you seem to be doing alright lol :)

Answer 7

For example if you put in a number very very close to zero from the left (very very very small but negative) you will get a value and then it will be made positive, but then the denominator would make it negative. From the right the limit would be positive. so DNE!

Answer 8

Thanks haha only the new stuff!

Answer 9

lol well you're acing it all! I'll adding you as a fan. Thanks!

Answer 10

No problem!