Question

How can I solve the following? (attached)

Answer 1

Sample problem:

Answer 2

What step are you confused on the sample problem?

Answer 3

I understand the sample problem. I just don't know how to use it for the actual problem.

Answer 4

do the same...instead of using 7 use 5

Answer 5

I did, but it shows up as wrong when I put it in.

Answer 6

then you did something wrong. ...show me the steps

Answer 7

what is the final answer that you got when you did the problem?

Answer 8

Nevermind, I found my error, instead of 2/9 I put 2/5. Sorry. Can you help me with another problem though?

Answer 9

yes sure....remember to follow all the steps and make sure you don't make a mistake. One small mistake can make the answer wrong

Answer 10

Sample:

Answer 11

What's the first step? Let's make the square root into an exponent
\[\int\limits_{3}^{7}\frac{1}{\sqrt{6x+7}}dx\]\[\int\limits_{3}^{7}\frac{1}{(6x+7)^\frac{1}{2}}dx\]

Answer 12

then we bring the denominator to the top. But in order to do this we have to make the exponent a negative. Then we get
\[\int\limits_{3}^{7}(6x+7)^{-\frac{1}{2}}dx\]

Answer 13

You just integrate what's inside first....can you tell me what you get?

Answer 14

3x^2+7x+C

Answer 15

No that's not it. Look back in the problem you did before and see how they integrated a square root after it became
\[(-------)^\frac{1}{2}\]

Answer 16

you have to do the chain rule.

Answer 17

Try it one more time....what is the integral?

Answer 18

I have no idea here..

Answer 19

I thought you know how to integrate something that was a square root. Look at the example problem you did before and see what happens.

Answer 20

Would it be:
1/12 root of 6x+7?

Answer 21

Is the answer 1/4? If yes, then I've done my work correct.

Answer 22

I think you made a mistake
\[\frac{1}{6} *\frac{1}{2}=\frac{1}{12}\]

that's how you got the 12 right?

Answer 23

Yes

Answer 24

it's suppose to be\[\frac{1}{6}*2=\frac{2}{3}=\frac{1}{3}\]

Answer 25

1/3 root of 6x+7


not 1/12 root of 6x+7

Answer 26

Oh, so then the answer would be: 1.

Answer 27

what no I got something else

Answer 28

\[\frac{1}{3}\sqrt{6x+7}\]\[\frac{1}{3}\sqrt{6(7)+7}-\frac{1}{3}\sqrt{6(3)+7}\]

Answer 29

\[\frac{1}{3}(\sqrt{6(7)+7}-\sqrt{6(3)+7})\]\[\frac{1}{3}(\sqrt{42+7}-\sqrt{18+7})\]

Answer 30

can you do the rest?

Answer 31

Yes, I got it.

Answer 32

what did you get?

Answer 33

Im doing the math right now.

Answer 34

ok tell me what you get just to check if you got it right.

Answer 35

2/3

Answer 36

yeah that's what I got good job.

Answer 37

If you have more problems post them in a different question.

Answer 38

I want to give you more medals :) for the good job