Simplify 5 root(4)(256x^3) completely. Write answer in radical form. Assume x>0.
\[\Large 5\sqrt[4]{256x^3}?\]
hint: \[\sqrt[4]{256x^3} \implies \sqrt[4]{4 \times 4 \times 4 \times 4 \times x^3}\] does that help?
@lgbasallote So thats what its wanting me to do?
depends on how you interpreted what i said..
so would it be 16xroot(4)(x)
@lgbasallote
nope..
\[\sqrt[4]{4 \times 4 \times 4 \times 4 \times x^3} \implies \sqrt[4]{4^4 \times x^3} \implies \sqrt[4]{4^4} \times \sqrt[4]{x^3}\]
Oh I sort it... so its 256/4
is that giving you an idea now?
Yeah so is it 4xroot(4)(x)
@lgbasallote
Am I right now?
still no
\[\Large \sqrt[4]{x^3} \ne x\sqrt[4]{x}\]
\[\sqrt[4]{x^5} = x\sqrt[4]{x}\]
OMG! This is so frustrating I feel dumb :(
you cant take x^3 out of the 4th root
I still don't get but you can take 2 and leave one x inside right? what happenes to the 256 I still don't get it? Thats not divided by four
@lgbasallote
it's not divided by 4
if it's \(\sqrt x^3\) then you're right it's \(x\sqrt x\) however it's 4th root
so you cant do it
\[\sqrt x^3 = x^{3/2} \] \[\sqrt[4]{x^3} = x^{3/4}\] do you see the difference?
i dont get where you're getting confused...will you tell me where?
i think you're too accustomed to square root that you're looking at this like square root. this is 4th root
So then it cant be done?
@lgbasallote
perhaps a demonstration \[\large \sqrt[4]{16 x^2} \implies \sqrt[4]{2 \times 2 \times 2 \times 2 \times x^2} \implies \sqrt[4]{2^4 x^2} \implies 2\sqrt[4]{x^2} \implies 2\sqrt x\]
here's another one \[\large \sqrt[4]{81x^3} \implies \sqrt[4]{3 \times 3 \times 3 \times 3 \times 3 \times x^3} \implies \sqrt[4]{3^4 x^3} \implies 3\sqrt[4]{x^3}\]
so then its root(4)(4^4x^3) 4root(4)(x^3) ? @lgbasallote
another one \[\large\sqrt[4]{256x^5} \implies \sqrt[4]{4 \times 4 \times 4 \times 4 \times x^5} \implies \sqrt[4]{4^4 x^5} \implies 4x\sqrt[4]{x}\]
yes!!!
but wiat..that's just \[\sqrt[4]{256x^3}\] remember the question is \[\large 5\sqrt[4]{256x^3}\]
so then you do \[5 \times 4 \sqrt[4]{x^3}\]
\[20\root(4)\sqrt{x^3}\]
20root(4)(X^3)
right
WOOOOO THANKS SO MUCHHHHH!!!! :D YOU ARE THE BEST!!! @lgbasallote
haha you're welcome ^_^
@lgbasallote So how would I do -5root(5)(32x^13)
32 = 2^5
\[\large\sqrt[5]{32x^{13}} \implies \sqrt[5]{2^5 x^{13}}\]
\[\implies \sqrt[5]{2^5 \times x^{10} \times x^3}\]
do you see it now?
2x^2root(5)(x^3) ? @lgbasallote
yes!!!
WOOOOOO!!! Now I get it more it's just confusing the sqrt gets me every time @lg
i need to go now so i hope you get these :DDD
haha i know..it just takes practice and experience
Thanks so m,ouch again! God Bless!!!! @lgbasallote
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