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Mathematics 22 Online
OpenStudy (anonymous):

A model rocket is launched with an initial upward velocity of . The rocket's height (in feet) after seconds is given by the following.

OpenStudy (anonymous):

velocity 201 93ft in air

OpenStudy (anonymous):

So you're loooking for the time that it took?

OpenStudy (anonymous):

yes in sec

OpenStudy (anonymous):

okay, and is the velocity 201m/s2 ?

OpenStudy (anonymous):

velocity is 201ft/s.

OpenStudy (anonymous):

rockets height is 93 ft

OpenStudy (anonymous):

Right right, I appologize. So the initial Equation you want to use is Velocity=Distance/Time. (V=D/T) In this specific case, since you are looking for Time, you want to Cross Multiply the T with the V. Once you have done so, it should look like T=D/V. If you plug in the answer, it should be T=93Ft/201ft/s. So once you have simplified that equation. It should be T=\[93ft \div 201 ft/s ^{2}\]

OpenStudy (anonymous):

ah, I have to leave. someone else can finish simpylfying ths.

OpenStudy (anonymous):

thank you alot will somebody else take over?

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